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4.48 L of an ideal gas at STP requires 12.0 calories to raise its temperature by 15^(@)Cat constant volume .The C_(p) of the gas is |
Answer» <html><body><p>3 <a href="https://interviewquestions.tuteehub.com/tag/cal-412083" style="font-weight:bold;" target="_blank" title="Click to know more about CAL">CAL</a><br/>4 cal<br/>7 cal<br/> 6 cal</p>Solution :No. of molesin 4.48 L of ideal gas at STP`= ( 4.48 )/( 22.4) = 0.2` <br/>Thus, to raise the <a href="https://interviewquestions.tuteehub.com/tag/temperature-11887" style="font-weight:bold;" target="_blank" title="Click to know more about TEMPERATURE">TEMPERATURE</a> of0.2 mol of the ideal gas through `15^(@)<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a>`, heat absorbed `= 12 cal`. <br/> `:. ` To raise the temperature of 1 mol of the gas through `1^(@)C`, heat absorbed`= ( 12)/( 15) xx ( 1)/( 0.2) = 4 cal` i.e., `C_(v) = 4 cal` <br/> `:. C_(p) = C_(v) + <a href="https://interviewquestions.tuteehub.com/tag/r-611811" style="font-weight:bold;" target="_blank" title="Click to know more about R">R</a>= 4+2 cal = 6 cal`.</body></html> | |