4.48 L of an ideal gas at STP requires 12.0 calories to raise its temperature by 15^(@)Cat constant volume .The C_(p) of the gas is

4.48 L of an ideal gas at STP requires 12.0 calories to raise its temp

1.	4.48 L of an ideal gas at STP requires 12.0 calories to raise its temperature by 15^(@)Cat constant volume .The C_(p) of the gas is
Answer» 3 CAL 4 cal 7 cal 6 cal Solution :No. of molesin 4.48 L of ideal gas at STP`= ( 4.48 )/( 22.4) = 0.2` Thus, to raise the TEMPERATURE of0.2 mol of the ideal gas through `15^(@)C`, heat absorbed `= 12 cal`. `:. ` To raise the temperature of 1 mol of the gas through `1^(@)C`, heat absorbed`= ( 12)/( 15) xx ( 1)/( 0.2) = 4 cal` i.e., `C_(v) = 4 cal` `:. C_(p) = C_(v) + R= 4+2 cal = 6 cal`.