1.

4.6 g of sodium is treated with excess of water. Calcium the volume of hydrogen evolved at N.T.P

Answer»


Solution :`UNDERSET(2xx23=46g)(2Na+2H_(2)O)RARR underset(22400mL)(2NaOH+H_(2))`
46 g of Na evolve hydrogen at N.T.P = 22400 mL
4.6 g of Na evolve hydrogen at N.T.P `= (22400xx4.6)/(46)=2240mL`.


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