4 g of O_2 and 2g of H_2 are confined in a vessel of capacity 1 litre at 0^@C. Calculate the partial pressure of each gas, and

4 g of O_2 and 2g of H_2 are confined in a vessel of capacity 1 litre

1.	4 g of O_2 and 2g of H_2 are confined in a vessel of capacity 1 litre at 0^@C. Calculate the partial pressure of each gas, and
Answer» <html><body><p></p>Solution :<a href="https://interviewquestions.tuteehub.com/tag/calculation-907729" style="font-weight:bold;" target="_blank" title="Click to know more about CALCULATION">CALCULATION</a> of partial pressures : <br/> Volume of vessel = 1 L, `T = <a href="https://interviewquestions.tuteehub.com/tag/0-251616" style="font-weight:bold;" target="_blank" title="Click to know more about 0">0</a>^@<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a> = 273 <a href="https://interviewquestions.tuteehub.com/tag/k-527196" style="font-weight:bold;" target="_blank" title="Click to know more about K">K</a>` <br/> `:. "" PV = nRT " or " p = (nRT)/<a href="https://interviewquestions.tuteehub.com/tag/v-722631" style="font-weight:bold;" target="_blank" title="Click to know more about V">V</a>`<br/>`:.` Partial pressure of oxygen <br/>`Po_2=(nRT)/V =( 0.125 xx 0.0821 xx 273)/1 = 2.80` atm<br/>Similarly, partial pressure of hydrogen <br/> `P_(H_2)= (nRT)/V= (1xx0.0821 xx 273)/1= 22.4` atm</body></html>