4 grams of each pure huydrochloric acid and pure caustic soda are together dissolved in water. What weight of sodium chloride is obtained?

4 grams of each pure huydrochloric acid and pure caustic soda are toge

1.	4 grams of each pure huydrochloric acid and pure caustic soda are together dissolved in water. What weight of sodium chloride is obtained?
Answer» Solution :The STOICHIOMETRIC equation is given as `HCl+NaOH to NaCl+H_(2)O` 1 mole of HCl =1 mole of NaOH 36.5 grams of HCl=40 grams of NaOH NaOH is the limiting reagent. Therefore, the WEIGHT of NaCl obtained is LIMITED by NaOH 1 mole of NaOH=1 mole of NaCl 10 grams of NaOH=58.5 grams of NaCl 4 grams of NaOH=? The weight of sodium CHLORIDE obtained `=58.5 xx (4)/(40)=5.85"grams"`