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4 grams of each pure huydrochloric acid and pure caustic soda are together dissolved in water. What weight of sodium chloride is obtained? |
Answer» <html><body><p></p>Solution :The <a href="https://interviewquestions.tuteehub.com/tag/stoichiometric-1227930" style="font-weight:bold;" target="_blank" title="Click to know more about STOICHIOMETRIC">STOICHIOMETRIC</a> equation is given as <br/> `HCl+NaOH to NaCl+H_(2)O` <br/> 1 mole of HCl =1 mole of NaOH <br/> 36.5 grams of HCl=40 grams of NaOH <br/> NaOH is the limiting reagent. Therefore, the <a href="https://interviewquestions.tuteehub.com/tag/weight-1451304" style="font-weight:bold;" target="_blank" title="Click to know more about WEIGHT">WEIGHT</a> of NaCl obtained is <a href="https://interviewquestions.tuteehub.com/tag/limited-1074043" style="font-weight:bold;" target="_blank" title="Click to know more about LIMITED">LIMITED</a> by NaOH <br/> 1 mole of NaOH=1 mole of NaCl <br/> <a href="https://interviewquestions.tuteehub.com/tag/10-261113" style="font-weight:bold;" target="_blank" title="Click to know more about 10">10</a> grams of NaOH=58.5 grams of NaCl <br/> 4 grams of NaOH=? <br/> The weight of sodium <a href="https://interviewquestions.tuteehub.com/tag/chloride-915854" style="font-weight:bold;" target="_blank" title="Click to know more about CHLORIDE">CHLORIDE</a> obtained `=58.5 xx (4)/(40)=5.85"grams"`</body></html> | |