40 g f a gas occupies 20 dm^(3) at 300 K and 100 kPa pressure. If the pressure is changed to 50 lPa without changing to temperature, what would be its volume ?

40 g f a gas occupies 20 dm^(3) at 300 K and 100 kPa pressure. If the

1.	40 g f a gas occupies 20 dm^(3) at 300 K and 100 kPa pressure. If the pressure is changed to 50 lPa without changing to temperature, what would be its volume ?
Answer» Solution :`P_(1)v_(1)=P_(2)v_(2)` at constant temperature. `P_(1)=100 kPa, v_(1)=20 dm^(3), P_(2) =50 kPa, V_(2) ?` `V_(2)=(P_(1)V_(1))/(P_(2)),v_(2)=(100xx20)/(50)=40 dm^(3)` `:. V_(2)=40 dm^(3)`