40 g f a gas occupies 20 dm^(3) at 300 K and 100 kPa pressure. If the pressure is changed to 50 lPa without changing to temperature, what would be its volume ?

40 g f a gas occupies 20 dm^(3) at 300 K and 100 kPa pressure. If the

1.	40 g f a gas occupies 20 dm^(3) at 300 K and 100 kPa pressure. If the pressure is changed to 50 lPa without changing to temperature, what would be its volume ?
Answer» <html><body><p></p>Solution :`P_(1)v_(1)=P_(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)v_(2)` at constant temperature. <br/> `P_(1)=<a href="https://interviewquestions.tuteehub.com/tag/100-263808" style="font-weight:bold;" target="_blank" title="Click to know more about 100">100</a> kPa, v_(1)=<a href="https://interviewquestions.tuteehub.com/tag/20-287209" style="font-weight:bold;" target="_blank" title="Click to know more about 20">20</a> dm^(<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>), P_(2) =50 kPa, V_(2) ?` <br/> `V_(2)=(P_(1)V_(1))/(P_(2)),v_(2)=(100xx20)/(50)=40 dm^(3)` <br/> `:. V_(2)=40 dm^(3)`</body></html>