40 ml gaseous mixture of CO, CH_(4) and Ne was exploded with 10 ml of oxygen. On cooling, the gases occupied 36.5 ml. After treatment with KOH the volume reduced by 9 ml and again on treatment with alkaline pyrogallol, the volume further reduced, percentage of CH_(4) in the original mixture is

40 ml gaseous mixture of CO, CH_(4) and Ne was exploded with 10 ml of

1.	40 ml gaseous mixture of CO, CH_(4) and Ne was exploded with 10 ml of oxygen. On cooling, the gases occupied 36.5 ml. After treatment with KOH the volume reduced by 9 ml and again on treatment with alkaline pyrogallol, the volume further reduced, percentage of CH_(4) in the original mixture is
Answer» a. `22.4` B. `77.5` c. `7.5` d. `15` Solution :`underset(x)(CO)+(1)/(2)underset((x)/(2))(O_(2))rarrunderset(x)(CO_(2))` `underset(y)(CH_(4))+underset(2y)(2O_(2))rarrunderset(y)(CO_(2))+2H_(2)O` On passing through KOH, volume decrease due to `CO_(2)` absorption `impliesx+y=9….(1)` Final volume after reaction = `CO_(2)+Ne+"left over "O_(2)` `=(x+y)+(40-x-y)+(10-x//2-2y)` `36.5=50-(x)/(2)-2y` `x+4y=27....(2)` solving, `y=6,x=3` `IMPLIES %" of "CH_(4)=(6)/(40)xx100=15%`