40 ml of 0.1 Mammonia is mixed with 20 ml of 0.1 M HCl. What is the pH of the mixture ? ( pK_(b) of ammoniasolution is 4.74)

40 ml of 0.1 Mammonia is mixed with 20 ml of 0.1 M HCl. What is the pH

1.	40 ml of 0.1 Mammonia is mixed with 20 ml of 0.1 M HCl. What is the pH of the mixture ? ( pK_(b) of ammoniasolution is 4.74)
Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a>.74<br/><a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>.26<br/>9.26<br/>`5.00`</p>Solution :40 ml of 0.1 M `NH_(3)` solution `= 40xx0.1` millimole <br/> = 4 millimoles<br/> `NH_(4)OH+HCl rarr NH_(4)<a href="https://interviewquestions.tuteehub.com/tag/cl-408888" style="font-weight:bold;" target="_blank" title="Click to know more about CL">CL</a> + H_(2)O` <br/> 2 millimole of HCl will <a href="https://interviewquestions.tuteehub.com/tag/neutralize-7700166" style="font-weight:bold;" target="_blank" title="Click to know more about NEUTRALIZE">NEUTRALIZE</a> 2 millimoles of `NH_(4)OH` to form 2 millimoles of `NH_(4)Cl`. <br/> `NH_(4)OH` left = 60 ml <br/> `:. [NH_(4)OH]=(2)/(60)M, [NH_(4)Cl]=(2)/(60)M` <br/> `pOH=pK_(b)+<a href="https://interviewquestions.tuteehub.com/tag/log-543719" style="font-weight:bold;" target="_blank" title="Click to know more about LOG">LOG</a> .([NH_(4)Cl])/([NH_(4)OH])` <br/> `=4.74 + log .(2//60)/(2//60)=4.74` <br/> `:. pH=14-4.4.74=9.26`</body></html>