40 ml of a hydrocarbon undergoes combustion in 260 ml oxygen and gives 160 mlof CO_(2). If all volumes are measured under similar conditions of temperature and pressue, the formula of the hydrocarbon is

40 ml of a hydrocarbon undergoes combustion in 260 ml oxygen and gives

1.	40 ml of a hydrocarbon undergoes combustion in 260 ml oxygen and gives 160 mlof CO_(2). If all volumes are measured under similar conditions of temperature and pressue, the formula of the hydrocarbon is
Answer» `C_(3)H_(8)` `C_(4)H_(8)` `C_(6)H_(14)` `C_(4)H_(10)` Solution :`C_(4)H_(10)+(13)/(2)O_(2)rarr4CO_(2)+5H_(2)O` `40 ml-260 ml-160 ml`