40 ml of a hydrocarbon undergoes combustion in 260 ml oxygen and gives 160 mlof CO_(2). If all volumes are measured under similar conditions of temperature and pressue, the formula of the hydrocarbon is

40 ml of a hydrocarbon undergoes combustion in 260 ml oxygen and gives

1.	40 ml of a hydrocarbon undergoes combustion in 260 ml oxygen and gives 160 mlof CO_(2). If all volumes are measured under similar conditions of temperature and pressue, the formula of the hydrocarbon is
Answer» <html><body><p>`C_(3)H_(<a href="https://interviewquestions.tuteehub.com/tag/8-336412" style="font-weight:bold;" target="_blank" title="Click to know more about 8">8</a>)`<br/>`C_(4)H_(8)`<br/>`C_(6)H_(<a href="https://interviewquestions.tuteehub.com/tag/14-272882" style="font-weight:bold;" target="_blank" title="Click to know more about 14">14</a>)`<br/>`C_(4)H_(10)`</p>Solution :`C_(4)H_(10)+(13)/(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)O_(2)rarr4CO_(2)+5H_(2)O` <br/> `<a href="https://interviewquestions.tuteehub.com/tag/40-314386" style="font-weight:bold;" target="_blank" title="Click to know more about 40">40</a> ml-260 ml-160 ml`</body></html>