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400cc of N_2 at 600mm and 500cc of O_2 at 300mm are quantitatively transferred in to an empty vessel of X 2 L capacity. Calculate the pressure of the mixture and partial pressures. |
Answer» <html><body><p><<a href="https://interviewquestions.tuteehub.com/tag/p-588962" style="font-weight:bold;" target="_blank" title="Click to know more about P">P</a>></p>Solution :<a href="https://interviewquestions.tuteehub.com/tag/pressure-1164240" style="font-weight:bold;" target="_blank" title="Click to know more about PRESSURE">PRESSURE</a> of the final mixture `= P = (P_(1)V_(1) + P_(2)V_(2))/(V)` <br/> ` = (400 xx 600 + <a href="https://interviewquestions.tuteehub.com/tag/500-323288" style="font-weight:bold;" target="_blank" title="Click to know more about 500">500</a> xx 300)/(2000) = 195` mm <br/> <a href="https://interviewquestions.tuteehub.com/tag/partial-596556" style="font-weight:bold;" target="_blank" title="Click to know more about PARTIAL">PARTIAL</a> presssure of nitrogen ` = (P_(1)V_(1))/(V) = (400 xx 600)/(2000) = 120` mm <br/> Partial pressure of oxygen ` = (P_(2)V_(2))/(V) = (500 xx 300)/(2000) = <a href="https://interviewquestions.tuteehub.com/tag/75-334971" style="font-weight:bold;" target="_blank" title="Click to know more about 75">75</a>` mm</body></html> | |