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448 mL of a hydrocarbon, having C = 87.8%, H = 12.19%, weigh 1.64 g at S.T.P Determine the molecular formula of the compound.

Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :Calculation of <a href="https://interviewquestions.tuteehub.com/tag/empirical-445984" style="font-weight:bold;" target="_blank" title="Click to know more about EMPIRICAL">EMPIRICAL</a> formula: <br/> <img src="https://doubtnut-static.s.llnwi.net/static/physics_images/NTN_HCS_ISC_CHE_XI_P1_C01_E09_018_S01.png" width="80%"/> <br/> The empirical formula of hydrocarbon = `C_3H_5` Calculation of molecular formula : <br/> One gram mole of any gas occupies 22.4 <a href="https://interviewquestions.tuteehub.com/tag/l-535906" style="font-weight:bold;" target="_blank" title="Click to know more about L">L</a> or 22400 mL at S.T.R <br/> `<a href="https://interviewquestions.tuteehub.com/tag/therefore-706901" style="font-weight:bold;" target="_blank" title="Click to know more about THEREFORE">THEREFORE</a>` 448 mL at S.T.R of hydrocarbon weigh = 1.64 g<br/> `therefore 22400` mL at S.T.R of hydrocarbon will weigh<br/> `=1.64/448 xx 22400 = <a href="https://interviewquestions.tuteehub.com/tag/82-339053" style="font-weight:bold;" target="_blank" title="Click to know more about 82">82</a>.0 g` <br/> Hence, gram molecular mass of hydrocarbon = 82.0 g Empirical formula mass = `(3 xx 12.01) + (5 xx 1.008) = 41.07` <br/> `n=("gram molecular mass")/("Empirical formula mass") = 82/(41.07) = 2` <br/> `therefore` The molecular formula `=2 xx C_(3)H_(5)= C_(6)H_(10)`</body></html>


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