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45.6 L of dinitrogen reacted with 22.7 L of dioxygen and 45.4 L of nitrous oxide was formed. The reaction is given below : 2N_(2(g))+O_(2(g)) rarr 2N_(2)O_((g)) Which law is being obeyed in this experiment ? Write the statement of the law ?

Answer» <html><body><p> </p>Solution :For the reaction,`{:(2N_(2(g)),+,O_(2(g)),rarr,2N_(2)O_((g)),,),(<a href="https://interviewquestions.tuteehub.com/tag/2v-300496" style="font-weight:bold;" target="_blank" title="Click to know more about 2V">2V</a>,,<a href="https://interviewquestions.tuteehub.com/tag/1v-282855" style="font-weight:bold;" target="_blank" title="Click to know more about 1V">1V</a>,,2V,,):}` <br/> `(45.4)/(22.7)=2 (22.7)/(22.7)= 1 (45.4)/(22.7)=2` <br/> Hence, the ratio between the volumes of the reactants and the product in the given question is <a href="https://interviewquestions.tuteehub.com/tag/simple-1208262" style="font-weight:bold;" target="_blank" title="Click to know more about SIMPLE">SIMPLE</a> i.e., `2:1:2`. It follows the Gay-Lussac.s law of gaseous solution. <br/> Note : Gay-Lussac.s law of gaseous volumes, when gases combine or are produced in a <a href="https://interviewquestions.tuteehub.com/tag/chemical-914796" style="font-weight:bold;" target="_blank" title="Click to know more about CHEMICAL">CHEMICAL</a> reaction, they do so in a simple ratio by volume provided all gases are at same temperature and <a href="https://interviewquestions.tuteehub.com/tag/pressure-1164240" style="font-weight:bold;" target="_blank" title="Click to know more about PRESSURE">PRESSURE</a>.</body></html>


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