45.6 L of dinitrogen reacted with 22.7 L of dioxygen and 45.4 L of nitrous oxide was formed. The reaction is given below : 2N_(2(g))+O_(2(g)) rarr 2N_(2)O_((g)) Which law is being obeyed in this experiment ? Write the statement of the law ?

45.6 L of dinitrogen reacted with 22.7 L of dioxygen and 45.4 L of nit

1.	45.6 L of dinitrogen reacted with 22.7 L of dioxygen and 45.4 L of nitrous oxide was formed. The reaction is given below : 2N_(2(g))+O_(2(g)) rarr 2N_(2)O_((g)) Which law is being obeyed in this experiment ? Write the statement of the law ?
Answer» Solution :For the reaction,`{:(2N_(2(g)),+,O_(2(g)),rarr,2N_(2)O_((g)),,),(2V,,1V,,2V,,):}` `(45.4)/(22.7)=2 (22.7)/(22.7)= 1 (45.4)/(22.7)=2` Hence, the ratio between the volumes of the reactants and the product in the given question is SIMPLE i.e., `2:1:2`. It follows the Gay-Lussac.s law of gaseous solution. Note : Gay-Lussac.s law of gaseous volumes, when gases combine or are produced in a CHEMICAL reaction, they do so in a simple ratio by volume provided all gases are at same temperature and PRESSURE.