4Mg+10HNO_(3)to4Mg(NO_(3))_(2)+NH_(4)NO_(3)+3H_(2)O. In this reaction

1.	4Mg+10HNO_(3)to4Mg(NO_(3))_(2)+NH_(4)NO_(3)+3H_(2)O. In this reaction
Answer» 96 gms magnesium can reduce one mole of `HNO_(3)` EQUIVALENT weight of reduced `HNO_(3)` is `(1)/(8)th` of its molecular weight Entire `HNO_(3)` INVOLVED in the reaction is reduced `HNO_(3)` is reduced to the best possible extent Solution :Out of 10 MOLES of `HNO_(3)`, only 1 mole gets reduced by 4 moles of Mg. n - f of reduced `HNO_(3)=(+5-(-3))=8`

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