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5.0 cm^(3) of H_(2)O_(2) liberates 0.508 g of iodine from an acidified KI solution. The strength of H_(2)O_(2) solution in terms of volume strenth at STP is

Answer» <html><body><p>6.48 volumes <br/>4.48 volumes <br/>7.68 volumes <br/>none of these </p>Solution :The reaction between `H_(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)O_(2)` and the acidified <a href="https://interviewquestions.tuteehub.com/tag/ki-533104" style="font-weight:bold;" target="_blank" title="Click to know more about KI">KI</a> solution is <br/> `2KI+H_(2)SO_(4)+underse(5.0 cm^(3))underset(34 g)(H_(2)O_(2))rarr K_(2)SO_(4)+2H_(2)O+underset(0.508 g)underset(254 g)(I_(2))` <br/> Then, Mass of `H_(2)O_(2)` that liberates 0.508 g of `I_(2)` <br/> `= (34)/(254)xx0.508 = 0.068 g` <br/> This much `H_(2)O_(2)` is present in `5.0 cm^(3)`. <br/> Hydrogen <a href="https://interviewquestions.tuteehub.com/tag/peroxide-1151683" style="font-weight:bold;" target="_blank" title="Click to know more about PEROXIDE">PEROXIDE</a> decomposes as follows : <br/> `underset(2xx34 g=68 g)underset(2 mol)(2H_(2)O_(2))rarr 2H_(2)O underset(22400 cm^(3)"(at STP)")underset(1 mol)(+O_(2))` <br/> Then 68 g of `H_(2)O_(2)` <a href="https://interviewquestions.tuteehub.com/tag/gives-1007647" style="font-weight:bold;" target="_blank" title="Click to know more about GIVES">GIVES</a> 22400 `cm^(3)` of oxygen <br/> 1 g of `H_(2)O_(2)` gives `(22400 cm^(3))/(68)` of oxygen <br/> 0.068 g of `H_(2)O_(2)` gives `(22400 cm^(3))/(68 g)xx 0.068 g = 22.4 cm^(3)` of oxygen <br/> Thus, `5 cm^(3)` of `H_(2)O_(2)` gives `22.4 cm^(3)` of oxygen at STP<br/> So, `1 cm^(3)` of `H_(2)O_(2)` gives `(22.4)/(5)cm^(3)` of oxygen at STP `= 4.48 cm^(3)` at STP <br/> <a href="https://interviewquestions.tuteehub.com/tag/therefore-706901" style="font-weight:bold;" target="_blank" title="Click to know more about THEREFORE">THEREFORE</a>, strength of the given `H_(2)O_(2)` sample = 4.48 volumes.</body></html>


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