5.6 L of a gas at NTP weighs equal to 8g. The vapour density of gas is

1.	5.6 L of a gas at NTP weighs equal to 8g. The vapour density of gas is
Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/32-307188" style="font-weight:bold;" target="_blank" title="Click to know more about 32">32</a><br/><a href="https://interviewquestions.tuteehub.com/tag/16-276476" style="font-weight:bold;" target="_blank" title="Click to know more about 16">16</a><br/>8<br/>40<br/></p>Solution :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a>) `therefore` 5.6 L of gas weighs at NTP = 8g <br/> `therefore` L of gas will weights at NTP = (8 <a href="https://interviewquestions.tuteehub.com/tag/xx-747671" style="font-weight:bold;" target="_blank" title="Click to know more about XX">XX</a> 22.4)/(5.6) = 32g <br/> `therefore` Molecular weight of gas = 32 <br/> We know that, Molecular weight = <a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a> xx vapour density <br/> `therefore` Vapour density = `32/2` = 16</body></html>

Discussion