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5.82 g of a silver coin is dissolved in nitric acid. One adding solution, all the silver present gets precipitated as AgCl. The weight of the precipitate is found to be 7.20 g. What is the percentage of silver in the coin ?

Answer» <html><body><p><br/></p>Solution :<a href="https://interviewquestions.tuteehub.com/tag/weight-1451304" style="font-weight:bold;" target="_blank" title="Click to know more about WEIGHT">WEIGHT</a> of AgCl <a href="https://interviewquestions.tuteehub.com/tag/precipitated-2948214" style="font-weight:bold;" target="_blank" title="Click to know more about PRECIPITATED">PRECIPITATED</a> = 7.20 g <br/> Weight of silver in the preciptate `= ((<a href="https://interviewquestions.tuteehub.com/tag/108g-1773491" style="font-weight:bold;" target="_blank" title="Click to know more about 108G">108G</a>))/((143.50g))xx(7.20g)=5.42g` <br/> <a href="https://interviewquestions.tuteehub.com/tag/percentage-13406" style="font-weight:bold;" target="_blank" title="Click to know more about PERCENTAGE">PERCENTAGE</a> of silver in the <a href="https://interviewquestions.tuteehub.com/tag/coin-921316" style="font-weight:bold;" target="_blank" title="Click to know more about COIN">COIN</a> `= ((5.42g))/((5.83g))xx100=93.1%`.</body></html>


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