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5.82 g of a silver coin were dissolved in strong nitric acid and excess of NaCI solution was added. The silver chloride precipitated was dried and weighed 7.20 g. Calculate the percentage of silver in the coin

Answer» <html><body><p><br/></p>Solution :The corresponding <a href="https://interviewquestions.tuteehub.com/tag/chemical-914796" style="font-weight:bold;" target="_blank" title="Click to know more about CHEMICAL">CHEMICAL</a> equations are: <br/> `underset("one mole" 107.9 g) (2HNO_(3)) to underset("one mole")(AgNO_(3)) + NO_(2) + H_(2)O` <br/>`underset("One mole")(AgNO_(3)) + NaCl to underset("one mole" <a href="https://interviewquestions.tuteehub.com/tag/143-273618" style="font-weight:bold;" target="_blank" title="Click to know more about 143">143</a>.35 g)(<a href="https://interviewquestions.tuteehub.com/tag/agcl-368919" style="font-weight:bold;" target="_blank" title="Click to know more about AGCL">AGCL</a>) <a href="https://interviewquestions.tuteehub.com/tag/darr-943899" style="font-weight:bold;" target="_blank" title="Click to know more about DARR">DARR</a> + NaNO_(3)` <br/> From the equations, it is clear that one mole (107.9 g) of Ag gives one mole (143. 35 g) of AgCI. <br/> `therefore` The mass of Ag which gives 7.20 g of AgCI<br/> `=107.9/143.35 <a href="https://interviewquestions.tuteehub.com/tag/xx-747671" style="font-weight:bold;" target="_blank" title="Click to know more about XX">XX</a> 7.20 = 5.42 g` <br/> `therefore` Percentage of Ag in the given coin <br/> `=5.42/5.82 xx 100 = 93.1`</body></html>


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