5 g of an unknown hgas has pressure P at temperature TK in a vessel. On increasing the temperature by 50^(@)C, 1g of the was given out to maintain the pressure P. What was the original temperature of the gas ?

5 g of an unknown hgas has pressure P at temperature TK in a vessel. O

1.	5 g of an unknown hgas has pressure P at temperature TK in a vessel. On increasing the temperature by 50^(@)C, 1g of the was given out to maintain the pressure P. What was the original temperature of the gas ?
Answer» <html><body><p><<a href="https://interviewquestions.tuteehub.com/tag/p-588962" style="font-weight:bold;" target="_blank" title="Click to know more about P">P</a>></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :Initially,`T_(1)=T,P_(1)=P,V_(1)=<a href="https://interviewquestions.tuteehub.com/tag/v-722631" style="font-weight:bold;" target="_blank" title="Click to know more about V">V</a> `(Volume of the <a href="https://interviewquestions.tuteehub.com/tag/vessel-1445872" style="font-weight:bold;" target="_blank" title="Click to know more about VESSEL">VESSEL</a>), `n_(1)=(5)/(M)`<a href="https://interviewquestions.tuteehub.com/tag/mole-1100299" style="font-weight:bold;" target="_blank" title="Click to know more about MOLE">MOLE</a><br/> Finally,`T_(2)=(T+50)K, P_(2)=P, V_(2)=V, n_(2)=(5-1)/(M)=(4)/(M)` mole <br/> (Increase of `50^(@)C`=increase of 50 K because size of `1^(@)C`=1 K) <br/> ApplyingPV=nRT <br/> `n_(1)T_(1)=n_(2)T_(2)` <br/> `(5)/(M)xxT=(4)/(M)(T+50)"or"5T=4T+200"orT=200 K`</body></html>