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5 g of an unknown hgas has pressure P at temperature TK in a vessel. On increasing the temperature by 50^(@)C, 1g of the was given out to maintain the pressure P. What was the original temperature of the gas ?

Answer»

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SOLUTION :Initially,`T_(1)=T,P_(1)=P,V_(1)=V `(Volume of the VESSEL), `n_(1)=(5)/(M)`MOLE
Finally,`T_(2)=(T+50)K, P_(2)=P, V_(2)=V, n_(2)=(5-1)/(M)=(4)/(M)` mole
(Increase of `50^(@)C`=increase of 50 K because size of `1^(@)C`=1 K)
ApplyingPV=nRT
`n_(1)T_(1)=n_(2)T_(2)`
`(5)/(M)xxT=(4)/(M)(T+50)"or"5T=4T+200"orT=200 K`


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