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5 moles of SO_(2)and 5 " molesof " O_(2)are allowed to react . At equilibrium , it was found that 60%SO_(2) is used up . If the pressure of the mixture is one atmosphere, the partialpressureof O_(2) is

Answer» <html><body><p>`0*52` atm<br/>`0*21` atm<br/>` 0*41`atm<br/>`0*82` atm</p>Solution :` {:(,<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a> SO_(2)(g),+,O_(2)(g),hArr,2 SO_(3)(g)),("Intial",<a href="https://interviewquestions.tuteehub.com/tag/5-319454" style="font-weight:bold;" target="_blank" title="Click to know more about 5">5</a>,,5,,0):}` <br/> As 60 % `SO_(2)` is used up, no of moles of `SO_(2) "used up" = 60/100 xx 5 =3`<br/> ` :. " No. of moles of " SO_(2) " at equilibrium " = 5-3=2` <br/> As 2 moles of `SO_(2) " <a href="https://interviewquestions.tuteehub.com/tag/react-613674" style="font-weight:bold;" target="_blank" title="Click to know more about REACT">REACT</a> with <a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a> mole of " O_(2)` <br/>`=1/2 xx 3 = 1.5 " moles" ` <br/> i.e. No. of moles of `O_(2)` at equilibrium<br/> `=5-1*5 = 3.5 ` <br/> As 2 moles of `SO_(2) " produce 2 molesof " SO_(3) ` <br/> `:. " No . of moles of "SO_(3)" equilibrium = 3 moles"`<br/> `= 2 + 3*5 + 3 = 8*5 ` <br/> As 2 moles of `SO_(2)"produce 2 moles of"SO_(3)` <br/> ` :. " No. of moles of " SO_(3) " at equilibrium" = 3 moles ` <br/> `:. "<a href="https://interviewquestions.tuteehub.com/tag/total-711110" style="font-weight:bold;" target="_blank" title="Click to know more about TOTAL">TOTAL</a> no. of moles at equilibrium "` <br/></body></html>


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