5 moles of SO_(2)and 5 " molesof " O_(2)are allowed to react . At equilibrium , it was found that 60%SO_(2) is used up . If the pressure of the mixture is one atmosphere, the partialpressureof O_(2) is

5 moles of SO_(2)and 5 " molesof " O_(2)are allowed to react . At equi

1.	5 moles of SO_(2)and 5 " molesof " O_(2)are allowed to react . At equilibrium , it was found that 60%SO_(2) is used up . If the pressure of the mixture is one atmosphere, the partialpressureof O_(2) is
Answer» `052` atm `021` atm ` 041`atm `082` atm Solution :` {:(,2 SO_(2)(g),+,O_(2)(g),hArr,2 SO_(3)(g)),("Intial",5,,5,,0):}` As 60 % `SO_(2)` is used up, no of moles of `SO_(2) "used up" = 60/100 xx 5 =3` ` :. " No. of moles of " SO_(2) " at equilibrium " = 5-3=2` As 2 moles of `SO_(2) " REACT with 1 mole of " O_(2)` `=1/2 xx 3 = 1.5 " moles" ` i.e. No. of moles of `O_(2)` at equilibrium `=5-15 = 3.5 ` As 2 moles of `SO_(2) " produce 2 molesof " SO_(3) ` `:. " No . of moles of "SO_(3)" equilibrium = 3 moles"` `= 2 + 35 + 3 = 8*5 ` As 2 moles of `SO_(2)"produce 2 moles of"SO_(3)` ` :. " No. of moles of " SO_(3) " at equilibrium" = 3 moles ` `:. "TOTAL no. of moles at equilibrium "`