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50 litre of dry N_(2) is passed through 36g of H_(2)O" at "27^(@)C. After passage of gas, there is a loss of 1.20g in water. Calculate vapour pressure of water. |
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Answer» Solution :The WATER vapours occupies the volume of `N_(2)` gas i.e. 50 litre For `H_(2)O` vapour V=50 litre, w=1.20g, T=300 K, `m=18g MOL^(-1)` `PV=w"/"mRT" or "Pxx50=1.2"/"18xx0.0821xx300` `:. P=0.03284 ATM =24.95 mm`. |
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