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50 litres of water containing Ca(HCO_3)_2 when converted into soft water required 22.2 g of Ca(OH)_2. Calculate the amount of Ca(HCO_3)_2 per litre of hard water. |
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Answer» `UNDERSET(162.116 g)(Ca(HCO_(3))_(2) + underset(74.096 g)(Ca(OH)_(2)) to 2CaCO_(3) + 2H_(2)O` `therefore74.096 g` of `Ca(OH)_(2)` react with `Ca(HCO_(3))_(2) = 162.116 g` `therefore 22.2` g of `Ca(OH)_(2)` will react with `Ca(HCO_(3))_(2)` `=(162.116)/(74.096) xx 22.2 = 48.6 g` This much `Ca (HCO_3)_2` is present in 50 litres of hard WATER. `therefore`The amount of `Ca (HCO_3)_2` in one litre of hard water. `=48.06/50 = 0.972 g` |
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