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50 litres of water containing Ca(HCO_3)_2 when converted into soft water required 22.2 g of Ca(OH)_2. Calculate the amount of Ca(HCO_3)_2 per litre of hard water. |
Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :The corresponding chemical equation is: <br/> `<a href="https://interviewquestions.tuteehub.com/tag/underset-3243992" style="font-weight:bold;" target="_blank" title="Click to know more about UNDERSET">UNDERSET</a>(162.116 g)(Ca(HCO_(3))_(2) + underset(74.096 g)(Ca(OH)_(2)) to 2CaCO_(3) + 2H_(2)O` <br/> `therefore74.096 g` of `Ca(OH)_(2)` react with `Ca(HCO_(3))_(2) = 162.116 g` <br/> `therefore 22.2` g of `Ca(OH)_(2)` will react with `Ca(HCO_(3))_(2)` <br/> `=(162.116)/(74.096) xx 22.2 = 48.6 g` <br/> This much `Ca (HCO_3)_2` is present in 50 litres of hard <a href="https://interviewquestions.tuteehub.com/tag/water-1449333" style="font-weight:bold;" target="_blank" title="Click to know more about WATER">WATER</a>. <br/> `therefore`The amount of `Ca (HCO_3)_2` in one litre of hard water. <br/> `=48.06/50 = 0.972 g`</body></html> | |