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50 mL of 0.1 M HCl and 50 mL of 2.0 M NaOH are mixed. The pH of the resulting solution isA. `1.30`B. `4.2`C. `12.70`D. `11.70` |
Answer» Correct Answer - C Mollimoles of HCl `=0.1 xx 50 =5 m mol` Millimoles of NaOH `=0.2 xx 50 = 10 m mol` `:. `Resulting solution contains 5 m mole of NaOH IN `(50+50)100` solution `:. [NaOH ]=(5 xx 10^(-3))/(100xx10^(-2))=5 xx 10^(-2)M` `[OH^(-)]=5 xx 10^(-2)M` `[H^(+)]=(K_(w))/([OH^(-)])=(10^(-14))/(5 xx 10^(-3))=(1)/(5) xx 10^(-12)` `=(10)/(5)xx 10^(-13) = 2 xx 10^(-13)` `pH =-log [H^(+)]=- log (2 xx 10^(-13))` `=13-log 2=13-0.3010=12.6990` |
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