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50 mL of 10 N H_(2)SO_(4), 25 mL of 12 N HCl and 40 mL of 5 N HNO_(3) are mixed and the volume of the mixture is made 1000 mL by adding water. The normality of the resulting solution will be : |
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Answer» Solution :`N_(1)V_(1)+N_(2)V_(2)+N_(3)V_(3)=N_(R )xxV_(R )` `10xx50+12xx25+5xx40=N_(R )=xx1000` `500+300+200=N_(R )=1000` `N_(R )=1` (Resulatnt normality) |
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