50 ml of gas A effuse through a pin -hole in 146 second . The same volume of CO_2 under identical condition effuse in 115 seconds . Calculate the molecular mass of A .

50 ml of gas A effuse through a pin -hole in 146 second . The same vol

1.	50 ml of gas A effuse through a pin -hole in 146 second . The same volume of CO_2 under identical condition effuse in 115 seconds . Calculate the molecular mass of A .
Answer» SOLUTION :`("Effusion rate of" CO_(2)) /("Effusion rate of A") = SQRT((M_(A))/(M_(CO_(2))))` `(50/115)/(50/146) = sqrt((M_(A))/(44)) , (1.27)^(2) = (M_(A))/(44)` `M_(A) = 71 therefore` MOLECULAR mass of A is 71 .