1.

50 ml solution of H_(2)O_(2) was treated with excess KI (s) and the solution was acidified with acetic acid. The liberated I_(2) required 40 ml of 0.5 M Na_(2)S_(2)O_(3) solution for the end point using starch is indicator. Find the molairty and volume strength of the H_(2)O_(2) solution.

Answer»

1.12 gm lit
2.24 gm/lit
5.6 gm/lit
NONE

Solution :Meq of `H_(2)O_(2)` M 50 ml
= m.eq of Hypo = `40xx0.5=20` meq
Now NORMALITY = `(20)/(50)=0.4N`
`IMPLIES M=0.2M`
`therefore` Volume strength = `Mxx11.2=0.2xx112=2.24gm//lit.`


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