50 ml solution of H_(2)O_(2) was treated with excess KI (s) and the solution was acidified with acetic acid. The liberated I_(2) required 40 ml of 0.5 M Na_(2)S_(2)O_(3) solution for the end point using starch is indicator. Find the molairty and volume strength of the H_(2)O_(2) solution.

50 ml solution of H_(2)O_(2) was treated with excess KI (s) and the so

1.	50 ml solution of H_(2)O_(2) was treated with excess KI (s) and the solution was acidified with acetic acid. The liberated I_(2) required 40 ml of 0.5 M Na_(2)S_(2)O_(3) solution for the end point using starch is indicator. Find the molairty and volume strength of the H_(2)O_(2) solution.
Answer» <html><body><p>1.12 gm lit<br/><a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>.24 gm/lit<br/>5.6 gm/lit <br/><a href="https://interviewquestions.tuteehub.com/tag/none-580659" style="font-weight:bold;" target="_blank" title="Click to know more about NONE">NONE</a> </p>Solution :Meq of `H_(2)O_(2)` M <a href="https://interviewquestions.tuteehub.com/tag/50-322056" style="font-weight:bold;" target="_blank" title="Click to know more about 50">50</a> ml <br/> = m.eq of Hypo = `40xx0.5=20` meq <br/> Now <a href="https://interviewquestions.tuteehub.com/tag/normality-1124423" style="font-weight:bold;" target="_blank" title="Click to know more about NORMALITY">NORMALITY</a> = `(20)/(50)=0.4N` <br/> `<a href="https://interviewquestions.tuteehub.com/tag/implies-1037962" style="font-weight:bold;" target="_blank" title="Click to know more about IMPLIES">IMPLIES</a> M=0.2M` <br/> `therefore` Volume strength = `Mxx11.2=0.2xx112=2.24gm//lit.`</body></html>