500 mL of 0.1 M KCl, 200 ml of 0.01 M NaNO_(3) and 500 ml of 0.1 M AgNO_(3) was mixed. The molarity of K^(+),Ag^(+), Cl^(-), Na^(+), NO^(3-) in the solution would be:

500 mL of 0.1 M KCl, 200 ml of 0.01 M NaNO_(3) and 500 ml of 0.1 M AgN

1.	500 mL of 0.1 M KCl, 200 ml of 0.01 M NaNO_(3) and 500 ml of 0.1 M AgNO_(3) was mixed. The molarity of K^(+),Ag^(+), Cl^(-), Na^(+), NO^(3-) in the solution would be:
Answer» `[K^(+)] = 0.04, [AG^(+)]= 0.04, {Na^(+)]=0.002[Cl^(-)] = 0.04 , [NO_(3^(-)] = 0.042` `[K^(+)]=0.04, [Na^(+)] = 0.00166, [NO^(-_(3)]]= 0.0433` `[K^(+)]= 0.04, [Ag^(+)] = 0.05, [Na^(+)] = 0.0025, [Cl^(-)] = 0.05, [NO^(-_(3)] = 0.0525]` `[K^(+)] = 0.05, [Na^(+)]= 0.0025 [Cl^(-)]= 0.05, [NO^(-_(3)] = 0.0525` ANSWER :B