500 mL of 0.1 M KCl, 200 ml of 0.01 M NaNO_(3) and 500 ml of 0.1 M AgNO_(3) was mixed. The molarity of K^(+),Ag^(+), Cl^(-), Na^(+), NO^(3-) in the solution would be:

500 mL of 0.1 M KCl, 200 ml of 0.01 M NaNO_(3) and 500 ml of 0.1 M AgN

1.	500 mL of 0.1 M KCl, 200 ml of 0.01 M NaNO_(3) and 500 ml of 0.1 M AgNO_(3) was mixed. The molarity of K^(+),Ag^(+), Cl^(-), Na^(+), NO^(3-) in the solution would be:
Answer» <html><body><p>`[<a href="https://interviewquestions.tuteehub.com/tag/k-527196" style="font-weight:bold;" target="_blank" title="Click to know more about K">K</a>^(+)] = 0.04, [<a href="https://interviewquestions.tuteehub.com/tag/ag-362275" style="font-weight:bold;" target="_blank" title="Click to know more about AG">AG</a>^(+)]= 0.04, {Na^(+)]=0.002[Cl^(-)] = 0.04 , [NO_(<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>^(-)] = 0.042`<br/>`[K^(+)]=0.04, [Na^(+)] = 0.00166, [NO^(-_(3)]]= 0.0433`<br/>`[K^(+)]= 0.04, [Ag^(+)] = 0.05, [Na^(+)] = 0.0025, [Cl^(-)] = 0.05, [NO^(-_(3)] = 0.0525]`<br/>`[K^(+)] = 0.05, [Na^(+)]= 0.0025 [Cl^(-)]= 0.05, [NO^(-_(3)] = 0.0525`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html>