1.

56.0 g KOH, 138.0 g K_(2)CO_(3) and 100.0 g KHCO_(3) is dissolved in water and the solution is made 1 L. 10 " mL of " this stock solution is titrated with 2.0 M HCl. Which of the following statements is/are correct?

Answer» <html><body><p>When phenolphthalein is used as an indicator from the very beginning the titre value of HCl will be <a href="https://interviewquestions.tuteehub.com/tag/60-328817" style="font-weight:bold;" target="_blank" title="Click to know more about 60">60</a> mL<br/>When phenolphthalein is used as an indicator from the very beginning the titre value of HCl will be 40 mL.<br/>When methyl orange is used as an indicator from the very beginning, the titre value of HCl will be 80 mL.<br/>When methyl orange is used as an indicator after the first end point the titre value of HCl will be 30 mL.</p>Solution :`m" Eq of "`(KOH)/(L)=(56)/((56)/(<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>))xx10^(3)=100=(20)/(20)mL` solution m" Eq of "`(K_(2)CO_(3))/(L)=(138)/((138)/(2))xx10^(3)=200=(40)/(20)mL` solution <br/> `m" Eq of "(KHCO_(3))/(L)=(100)/((100)/(1))xx10^(3)=<a href="https://interviewquestions.tuteehub.com/tag/1000-265236" style="font-weight:bold;" target="_blank" title="Click to know more about 1000">1000</a>=(20)/(20)mL` <br/> (b). With phenolphthalein: <br/> `m" Eq of "KOH+(1)/(2)m" Eq of "K_(2)CO_(3)=m" Eq of "HCl` <br/> `20+(40)/(2)=vxx1N(n=1)` <br/> `V_(HCl)=40mL` <br/> (c). With methyl orange: <br/> `m" Eq of "KOH+m" Eq of "K_(2)CO_(3)+m" Eq of "KHCO_(3)=m" Eq of "HCl` <a href="https://interviewquestions.tuteehub.com/tag/ltbrgt-2804393" style="font-weight:bold;" target="_blank" title="Click to know more about LTBRGT">LTBRGT</a> `20+40+20=Vxx1N` <br/> `V_(HCl)=80mL` <br/> (d). With methyl orange after the first end point: <br/> `(1)/(2)m" Eq of "K_(2)CO_(3)+m" Eq of "KHCO_(3)=m" Eq of "HCl` <br/> `20+20=Vxx1N` <br/> `V_(HCl)=40mL`</body></html>


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