1.

6.02 xx 10^(20) molecules of urea are present in 100 mL of its solution. The concentration of urea solution is:

Answer»

0.001 M
0.01 M
0.02 M
0.1 M

Solution :No. of MOLES of urea taken `=(6.02 xx 10^(20))/(6.022 xx 10^(23)) = 10^(-3)`
`therefore` MOLARITY of solution `=10^(-3)/100 xx 1000 = 0.01 M`


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