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6.02 xx 10^(20) molecules of urea are present in 100 mL of its solution. The concentration of urea solution is: |
Answer» <html><body><p>0.001 M<br/>0.01 M<br/>0.02 M<br/>0.1 M </p>Solution :No. of <a href="https://interviewquestions.tuteehub.com/tag/moles-1100459" style="font-weight:bold;" target="_blank" title="Click to know more about MOLES">MOLES</a> of urea taken `=(6.02 xx 10^(20))/(6.022 xx 10^(23)) = 10^(-<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>)` <br/> `therefore` <a href="https://interviewquestions.tuteehub.com/tag/molarity-1100268" style="font-weight:bold;" target="_blank" title="Click to know more about MOLARITY">MOLARITY</a> of solution `=10^(-3)/<a href="https://interviewquestions.tuteehub.com/tag/100-263808" style="font-weight:bold;" target="_blank" title="Click to know more about 100">100</a> xx 1000 = 0.01 M`</body></html> | |