6.023xx10^(20) molecules of urea are present in 100 ml of its solution. The concentration of the solution is

6.023xx10^(20) molecules of urea are present in 100 ml of its solution

1.	6.023xx10^(20) molecules of urea are present in 100 ml of its solution. The concentration of the solution is
Answer» <html><body><p>0.001 M<br/>0.01 M<br/>0.02 M<br/>0.1 M</p>Solution :100 ml of solution contain `6.023 <a href="https://interviewquestions.tuteehub.com/tag/xx-747671" style="font-weight:bold;" target="_blank" title="Click to know more about XX">XX</a> 10^(20)` molecules. <br/>`6.023 xx 10^(23)` molecules in 1000 ml = 1 M <br/>`:. 6.023 xx 10^(20)` molecules in 1000 ml=`(1xx6.023xx10^(20))/(6.023xx10^(23))=10^(-3)` <br/>`10^(-3)` moles of <a href="https://interviewquestions.tuteehub.com/tag/present-1163722" style="font-weight:bold;" target="_blank" title="Click to know more about PRESENT">PRESENT</a> in 100 ml <br/>`:.` In 1000ml the moles present is=`10^(-3)/cancel(100)xxcancel(1000)=10^(-2)` moles <br/><a href="https://interviewquestions.tuteehub.com/tag/concentration-20558" style="font-weight:bold;" target="_blank" title="Click to know more about CONCENTRATION">CONCENTRATION</a> = 0.01 M</body></html>