6.023xx10^(20) molecules of urea are present in 100 ml of its solution. The concentration of the solution is

6.023xx10^(20) molecules of urea are present in 100 ml of its solution

1.	6.023xx10^(20) molecules of urea are present in 100 ml of its solution. The concentration of the solution is
Answer» 0.001 M 0.01 M 0.02 M 0.1 M Solution :100 ml of solution contain `6.023 XX 10^(20)` molecules. `6.023 xx 10^(23)` molecules in 1000 ml = 1 M `:. 6.023 xx 10^(20)` molecules in 1000 ml=`(1xx6.023xx10^(20))/(6.023xx10^(23))=10^(-3)` `10^(-3)` moles of PRESENT in 100 ml `:.` In 1000ml the moles present is=`10^(-3)/cancel(100)xxcancel(1000)=10^(-2)` moles CONCENTRATION = 0.01 M