6.3 g of oxalic acid dihydrate have been dissolved in water to obtain a 250 ml solution. How much volume of 0.1 N NaOH would be required to neutralize 10 mL of this solution ?

6.3 g of oxalic acid dihydrate have been dissolved in water to obtain

1.	6.3 g of oxalic acid dihydrate have been dissolved in water to obtain a 250 ml solution. How much volume of 0.1 N NaOH would be required to neutralize 10 mL of this solution ?
Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/40-314386" style="font-weight:bold;" target="_blank" title="Click to know more about 40">40</a> mL<br/>20 mL<br/>10 mL<br/>4 mL </p>Solution :<a href="https://interviewquestions.tuteehub.com/tag/eq-446394" style="font-weight:bold;" target="_blank" title="Click to know more about EQ">EQ</a>. wt of `overset(COOH)underset(COOH)(\|).2H_(2)O = 63`<br/> Normality of the solution prepared <br/> `N=(w xx 1000)/(E xx <a href="https://interviewquestions.tuteehub.com/tag/v-722631" style="font-weight:bold;" target="_blank" title="Click to know more about V">V</a>) = (6.3 xx 1000)/(63 xx 250) = 0.4 N` <br/> `underset(NaOH)(N_(1)V_(1)) = underset("<a href="https://interviewquestions.tuteehub.com/tag/oxalic-2906163" style="font-weight:bold;" target="_blank" title="Click to know more about OXALIC">OXALIC</a> acid")(N_(2)V_(2))` <br/> `therefore V_(1) = (N_(2)V_(2))/N_(1) =(0.4 xx 10)/0.1 = 40 mL`</body></html>