6.3 g of oxalic acid dihydrate have been dissolved in water to obtain a 250 ml solution. How much volume of 0.1 N NaOH would be required to neutralize 10 mL of this solution ?

6.3 g of oxalic acid dihydrate have been dissolved in water to obtain

1.	6.3 g of oxalic acid dihydrate have been dissolved in water to obtain a 250 ml solution. How much volume of 0.1 N NaOH would be required to neutralize 10 mL of this solution ?
Answer» 40 mL 20 mL 10 mL 4 mL Solution :EQ. wt of `overset(COOH)underset(COOH)(\|).2H_(2)O = 63` Normality of the solution prepared `N=(w xx 1000)/(E xx V) = (6.3 xx 1000)/(63 xx 250) = 0.4 N` `underset(NaOH)(N_(1)V_(1)) = underset("OXALIC acid")(N_(2)V_(2))` `therefore V_(1) = (N_(2)V_(2))/N_(1) =(0.4 xx 10)/0.1 = 40 mL`