6 grams of magnesite mineral on heating liberated carbondioxide which measures 1.12 L at STP. What is the percentage purity of mineral?

6 grams of magnesite mineral on heating liberated carbondioxide which

1.	6 grams of magnesite mineral on heating liberated carbondioxide which measures 1.12 L at STP. What is the percentage purity of mineral?
Answer» <html><body><p></p>Solution :<a href="https://interviewquestions.tuteehub.com/tag/chemical-914796" style="font-weight:bold;" target="_blank" title="Click to know more about CHEMICAL">CHEMICAL</a> constituent of magnesite is magnesium carbonate. On heating it <a href="https://interviewquestions.tuteehub.com/tag/liberates-1072974" style="font-weight:bold;" target="_blank" title="Click to know more about LIBERATES">LIBERATES</a> carbondioxide. <br/> `MgCO_(3) to MgO+CO_(2)` <br/> 1 mole of `CO_(2)="1 mole of "MgCO_(3)` <br/> 22.4 L of `CO_(2)` at STP=84 grams of `MgCO_(3)` <br/> 1.12 L of `CO_(2)` at STP=? <br/> The <a href="https://interviewquestions.tuteehub.com/tag/weight-1451304" style="font-weight:bold;" target="_blank" title="Click to know more about WEIGHT">WEIGHT</a> of pure `MgCO_(3)` to be decomposed <br/> `(1.12)/(22.4) xx 84 =4.2"grams"` <br/> Percent purity `=(4.2)/(6) xx 100=70%`</body></html>