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6 ml of a standard soap solution (1ml = 0.001g of CaCO_3 ) were required in titrating 50ml of water to produce a good lather. Calculate the degree of hardness. |
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Answer» Solution :50 ml of hard WATER sample REQUIRES 6 ml of soap solution. Volume of soap solution required for `10^6`ml of hardwater to get good lather ` = (10^6 XX 6)/(50)= 0.12 xx 10^6 ml` Given that if 1ML soap is required for the water sample to get good lather that sample contains 0.001g of `CaCO_3` 1ml soap `to 10^3 g CaCO_3` `0.12 xx 10^6` ml soap `to` Weight equivalent of `CaCO_3` = 120 g Degree of HARDNESS of water sample = 120ppm |
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