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60 mL of 0.3 M KOH and 40 mL of 0.2 M HCl are mixed. What is the pH of the mixture ? |
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Answer» SOLUTION :Milliequivalents of BASE =` 60 xx 0.3 = 18`. Milliequivalents of acid `= 40xx 0.2 = 8` RESULTANT hydroxyl ion concentration, `[OH^(-)] = (18 -8)/( 60+40 )= (10)/(100)=(1)/(10) = 0.1` ` pOH =- LOG(0.1 )=1` `[PH]=14 -pH` ` pH =14-1=13.` |
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