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60 mL of methane and 180mL of oxygen are mixed and fixed. The resulting gases are passed throughcaustic soda solution. Determine the composition of gases before and after passing through base solution. |
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Answer» Solution :The storichiometric equation is `underset((g))(CH_(4))+underset((g))(2O_(2))tounderset((g))(CO_(2))+underset((l))(2H_(2))O` `1 vol 2 vol 1vol ovol """Gay-Lussac.s coefficients"` `60mL 180mL 0mL 0mL """ at start"` `0mL 60mL 60mL 0mL "" "after the reaction" ` Before passing through caustic soda solution unreacted oxygen =60mL Carbondioxide FORMED =80ML After passing through caustic soda solution(since `CO_(2)` is ABSORBED) unreaced oxygen =60mL |
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