60 mL of methane and 180mL of oxygen are mixed and fixed. The resulting gases are passed throughcaustic soda solution. Determine the composition of gases before and after passing through base solution.

60 mL of methane and 180mL of oxygen are mixed and fixed. The resultin

1.	60 mL of methane and 180mL of oxygen are mixed and fixed. The resulting gases are passed throughcaustic soda solution. Determine the composition of gases before and after passing through base solution.
Answer» <html><body><p></p>Solution :The storichiometric equation is `underset((g))(CH_(4))+underset((g))(2O_(2))tounderset((g))(CO_(2))+underset((l))(2H_(2))O` <br/> `1 vol 2 vol 1vol ovol """Gay-Lussac.s coefficients"` <br/> `60mL 180mL 0mL 0mL """ at start"` <br/> `0mL 60mL 60mL 0mL "" "after the reaction" ` <br/> Before passing through caustic soda solution unreacted oxygen =60mL <br/> Carbondioxide <a href="https://interviewquestions.tuteehub.com/tag/formed-464209" style="font-weight:bold;" target="_blank" title="Click to know more about FORMED">FORMED</a> =<a href="https://interviewquestions.tuteehub.com/tag/80ml-1927563" style="font-weight:bold;" target="_blank" title="Click to know more about 80ML">80ML</a> <br/> After passing through caustic soda solution(since `CO_(2)` is <a href="https://interviewquestions.tuteehub.com/tag/absorbed-846166" style="font-weight:bold;" target="_blank" title="Click to know more about ABSORBED">ABSORBED</a>) <br/> unreaced oxygen =60mL</body></html>