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60g CH_(3)COOH and 46g C_(2)H_(5)OH react in 5L flask to form 44g CH_(3)COOC_(2)H_(5) at equilibrium. On taking 120 g CH_(3)COOH and 46g C_(2)H_(5)OH, CH_(3)COOC_(2)H_(5) formed at equilibrium is :

Answer» <html><body><p>44g<br/>20.33g<br/>22g<br/>58.66g</p>Solution :Molar mass of `CH_(3)COOH=60gmol^(-1)` <br/> Molar mass of `C_(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)H_(5)OH=46g mol^(-1)` <br/> Molar mass of `CH_(3)COOC_(2)H_(5)=88g mol^(-1)` <br/> `:. [CH_(3)COOH)_("Initial")=(<a href="https://interviewquestions.tuteehub.com/tag/60-328817" style="font-weight:bold;" target="_blank" title="Click to know more about 60">60</a>)/(60xx5)=0.2 "mol"L^(-1)` <br/> `[C_(2)H_(5)OH]_("Initial")=(46)/(46xx5)=0.2"mol" L^(-1)` <br/> `[CH_(3)COOC_(2)H_(5)]_(eqm)=(44)/(88)xx(1)/(5)=0.1 "mol" L^(-1)` <br/> `CH_(3)COOH+C_(2)H_(5)OH hArr CH_(3)COOC_(2)H_(5)+H_(2)O` <br/> Initial <br/> `0.2 M ""0.2M` <br/> At eqm. <br/> `(0.2-0.1)M""(0.2-0.1)M""0.1M""0.1M` <br/> `:. K=([CH_(3)COOC_(2)H_(5)][H_(2)O])/([CH_(3)COOH][C_(2)H_(5)OH])` <br/> `=(0.1xx0.1)/(0.1xx0.1)=1` <br/>In second case, <br/> `[CH_(3)COOH]_("Initial")=0.4M` <br/> `[C_(2)H_(5)OH]_("Initial")=0.2M` <br/><br/> If x is the amount of acid and <a href="https://interviewquestions.tuteehub.com/tag/alcohol-853024" style="font-weight:bold;" target="_blank" title="Click to know more about ALCOHOL">ALCOHOL</a> reacted <br/> `[CH_(3)COOH]_("eqm.")=(0.40-x)M` <br/> `[C_(2)H_(5)OH]_("eqm.")=[0.2-x]M` <br/> `[CH_(3)COOC_(2)H_(5)]_("eqm.")=[H_(2)O]_("eqm.")=xM` <br/> `:. K=(x^(2))/((0.4-x)(0.2-x))=1` <br/> `:. x^(2)=(0.4-x)(0.2-x)` <br/> `x^(2)=0.08+x^(2)-0.6x` <br/> `0.6x=0.08` <br/> `x=(8)/(60)M` <br/> `:. `Moles of ethyl acetate produced `=(8)/(60)<a href="https://interviewquestions.tuteehub.com/tag/xx5-2340058" style="font-weight:bold;" target="_blank" title="Click to know more about XX5">XX5</a>=(2)/(3)` <br/> Mass of ethyl acetate produced <br/> `=(2)/(3)xx88=58=58.66g`.</body></html>


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