60mL of pure ozone is heated and then colled. The increase in the volume is 10mL. Determine the percentage volume of ozone decomposed into oxygen.

60mL of pure ozone is heated and then colled. The increase in the volu

1.	60mL of pure ozone is heated and then colled. The increase in the volume is 10mL. Determine the percentage volume of ozone decomposed into oxygen.
Answer» <html><body><p></p>Solution :The balanced equations for the decomposed of ozone is <br/> `2O_(<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>)(g)to3O_(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)(g)` <br/> `2 vol "" 3vol"Gay-Lussac.s <a href="https://interviewquestions.tuteehub.com/tag/coefficients-920961" style="font-weight:bold;" target="_blank" title="Click to know more about COEFFICIENTS">COEFFICIENTS</a>"` <br/> `60mL "" "0mL at start"` <br/> `60-2x "" 3x "after the <a href="https://interviewquestions.tuteehub.com/tag/reaction-22747" style="font-weight:bold;" target="_blank" title="Click to know more about REACTION">REACTION</a>"` <br/> Total volume of the mixture after the reaction =60-2x+3x=60+10 <br/> <a href="https://interviewquestions.tuteehub.com/tag/solving-1217196" style="font-weight:bold;" target="_blank" title="Click to know more about SOLVING">SOLVING</a>, x=10 <br/> Volume of `O_(3)` decomposed =20mL <br/> Percentage volume of `O_(3)` decomposed `=(20/(60)xx100=33.3%)`</body></html>