

InterviewSolution
Saved Bookmarks
1. |
`6g` of a hydrocarbon on combustion in excess of oxygen produces `17.6g` of `CO_(2)` and `10.8g` of `H_(2)O`. The data illustrates the law of `:`A. conservation of massB. multiple proportionsC. constant proportionsD. reciprocal proportions |
Answer» Correct Answer - 1 `{:(C_(X)H_(Y)+,,O_(2),rarr,CO_(2),+,H_(2)O),(6g,,excess,,,,):}` mass of Hydrocarbon `=6g` mass of carbon `=(12)/(44)xx` mass of `CO_(2)=(12)/(44)xx17.6=4.8g` mass of Hydrogen `=(2)/(18)xx` mass of `H_(2)O=(2)/(18)xx10.8=1.2g` Total mass of carbon & Hydrogen `=4.8+1.2=6g` Mass of Hydrogen `=` Total mass of `(C+H)=6g`. Law of conservation of mass. |
|