7.00 g of a gas occupies a volume of 4.1 L at 300 K and 1 atm pressure. What is the molecular mass of the gas?

7.00 g of a gas occupies a volume of 4.1 L at 300 K and 1 atm pressure

1.	7.00 g of a gas occupies a volume of 4.1 L at 300 K and 1 atm pressure. What is the molecular mass of the gas?
Answer» <html><body><p></p>Solution :In the <a href="https://interviewquestions.tuteehub.com/tag/present-1163722" style="font-weight:bold;" target="_blank" title="Click to know more about PRESENT">PRESENT</a> case, <br/> `P= 1 " atm, " V= 4.1 L, T = 300 <a href="https://interviewquestions.tuteehub.com/tag/k-527196" style="font-weight:bold;" target="_blank" title="Click to know more about K">K</a>, m= 7.0 g, " and " R=0.0821 L " atm " K^(-1) mol^(-1)` <br/>`:."" <a href="https://interviewquestions.tuteehub.com/tag/pv-593601" style="font-weight:bold;" target="_blank" title="Click to know more about PV">PV</a> = m/M RT` <br/>`:."" M=(mRT)/(PV)= (7.0 xx0.0821 xx 300)/(1 x 4.1)= 42` <a href="https://interviewquestions.tuteehub.com/tag/amu-25369" style="font-weight:bold;" target="_blank" title="Click to know more about AMU">AMU</a><br/> and `:. ""d = m/V` <br/> `:. "" d=(7.0)/(4.1)=1.7g L^(-1)` <br/> Hence, the molecular mass of the given gas is 42 amu and its density in the given conditions is`1.7 g L^(-1)`.</body></html>