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7 grams of nitrogen is present at 127^@C and 16 grams of oxygen at 27^@C. Calculate (a) ratio of kinetic energy and (b) ratio of average kinetic energy of nitrogen and oxygen. |
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Answer» Solution :`(K.E) = 3/2 NRT ` For two gases ratio of KINETIC energies = ` ((K.E )_1)/((K.E)_2) = (n_1 T_1)/(n_2 T_2)= (7)/(28 ) xx 400 xx(32)/(16) xx (1)/(300 ) = 2:3` |
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