1.

70 gms of a metal oxide on reduction produced 54 gms of metal. The atomic weight of the metal is 81. What is its valency?

Answer»


Solution :wt. of metal oxide = 70 G
wt. of metal = 54 g
`therefore` wt of oxygen = `70-54=16g`
`(W_(1))/(W_(2))=(E_(1))/(E_(2)),("wt of metal")/("wt of oxygen")=("EQ wt of metal")/("EQ wt of oxygen")`
`(54)/(16)=(E)/(8)impliesE=27`
At. Wt = EQ wt `xx` valency
`81=27xx` valency implies Valency = 3


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