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70 gms of a metal oxide on reduction produced 54 gms of metal. The atomic weight of the metal is 81. What is its valency? |
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Answer» wt. of metal = 54 g `therefore` wt of oxygen = `70-54=16g` `(W_(1))/(W_(2))=(E_(1))/(E_(2)),("wt of metal")/("wt of oxygen")=("EQ wt of metal")/("EQ wt of oxygen")` `(54)/(16)=(E)/(8)impliesE=27` At. Wt = EQ wt `xx` valency `81=27xx` valency implies Valency = 3 |
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