720cc of methane diffused through a porous membrane in 30min. Under identical conditions 240cc of gas 'X'diffused in 20 min. Calculate the molecular weight of 'X'.

720cc of methane diffused through a porous membrane in 30min. Under id

1.	720cc of methane diffused through a porous membrane in 30min. Under identical conditions 240cc of gas 'X'diffused in 20 min. Calculate the molecular weight of 'X'.
Answer» <html><body><p></p>Solution :Rate of diffusion of methane ` = 720//30 = 24 "cc" m^(-<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>)` <br/> Rate of diffusion of gas .<a href="https://interviewquestions.tuteehub.com/tag/x-746616" style="font-weight:bold;" target="_blank" title="Click to know more about X">X</a>.`240//20 = 12 "cc" m^(-1)` <br/> Ratio of rates of diffusion is <a href="https://interviewquestions.tuteehub.com/tag/given-473447" style="font-weight:bold;" target="_blank" title="Click to know more about GIVEN">GIVEN</a> as `(r_(1))/(r_(2))= sqrt((M_(2))/(M_(1))) = (24)/(12) = 12` <br/> Molecular weight of .X. ` = 2^(2) <a href="https://interviewquestions.tuteehub.com/tag/xx-747671" style="font-weight:bold;" target="_blank" title="Click to know more about XX">XX</a> 16 = 64`</body></html>