720cc of methane diffused through a porous membrane in 30min. Under identical conditions 240cc of gas 'X'diffused in 20 min. Calculate the molecular weight of 'X'.

720cc of methane diffused through a porous membrane in 30min. Under id

1.	720cc of methane diffused through a porous membrane in 30min. Under identical conditions 240cc of gas 'X'diffused in 20 min. Calculate the molecular weight of 'X'.
Answer» Solution :Rate of diffusion of methane ` = 720//30 = 24 "cc" m^(-1)` Rate of diffusion of gas .X.`240//20 = 12 "cc" m^(-1)` Ratio of rates of diffusion is GIVEN as `(r_(1))/(r_(2))= sqrt((M_(2))/(M_(1))) = (24)/(12) = 12` Molecular weight of .X. ` = 2^(2) XX 16 = 64`