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8. From the following molar conductivities at infinite dilution, ∧^° for Al_2(SO_4)_3=858 S cm^2 mol^{-1} ∧^° for NH_4OH = 238.3 S cm^2 mol^{-1} ∧^° for (NH_4)_2SO_4 = 238.4 S cm^2 mol^{-1} Calculate ∧^° for Al(OH)_3

Answer» 8. From the following molar conductivities at infinite dilution, ∧^° for Al_2(SO_4)_3=858 S cm^2 mol^{-1} ∧^° for NH_4OH = 238.3 S cm^2 mol^{-1} ∧^° for (NH_4)_2SO_4 = 238.4 S cm^2 mol^{-1} Calculate ∧^° for Al(OH)_3


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