।8.The acid and water in two vessels A and B are in the4:3 and 2:3.

1.	।8.The acid and water in two vessels A and B are in the4:3 and 2:3. In what ratio should the liquids in boththe vessels be mixed to obtain a new mixture in vesselC containing half acid and half water ?दो बर्तनों A और B में अम्ल और पानी का अनुपात 4:3 और 2:3 है।दोनों बर्तनों के द्रव को किस अनुपात में मिलाया जाए ताकि बर्तन C में बनेनए मिश्रण में आधा अम्ल और आधा पानी हो?(a) 7:5 7657 ) 7:3 (d) 5:3
Answer» Ratios are 4:3 (4+3=7) and 2:3 (2+3=5). So LCM of 7, 5 is 35. Now, for 35 litres mixture . Let AC = Acid, W=water Vessel A, AC:W = 4:3 (4+3=7) means in 35 litres mixture. Acid is 4*35/7=20 litres and water is 3×35/7=15 litres. Vessel B, AC:W = 2:3(2+3=5) means in 35 litres mixture. Acid is 2×35/5 = 14 litres and water is 3×35/5 = 21 litres For Vessel C,AC:W=1:1(required) Let ratio of Vessel A=x and Vessel B=y. In Vessel C , both acid and water will be in equal quantity. So, Net quantity of acid = Net quantity of water 20x+14y=15x+21y 5x=7y x/y=7/5 So, x:y=7 :5 Vessel A : Vessel B = 7:5 (a) is correct option Right answer is a. 7:5. is carcat answer 7:5

।8.The acid and water in two vessels A and B are in the4:3 and 2:3. In what ratio should the liquids in boththe vessels be mixed to obtain a new mixture in vesselC containing half acid and half water ?दो बर्तनों A और B में अम्ल और पानी का अनुपात 4:3 और 2:3 है।दोनों बर्तनों के द्रव को किस अनुपात में मिलाया जाए ताकि बर्तन C में बनेनए मिश्रण में आधा अम्ल और आधा पानी हो?(a) 7:5 7657 ) 7:3 (d) 5:3

Answer»

Ratios are 4:3 (4+3=7) and 2:3 (2+3=5). So LCM of 7, 5 is 35.

Now, for 35 litres mixture .

Let AC = Acid, W=water

Vessel A,

AC:W = 4:3 (4+3=7) means in 35 litres mixture. Acid is 4*35/7=20 litres and water is 3×35/7=15 litres.

Vessel B,

AC:W = 2:3(2+3=5) means in 35 litres mixture. Acid is 2×35/5 = 14 litres and water is 3×35/5 = 21 litres

For Vessel C,AC:W=1:1(required)

Let ratio of Vessel A=x and Vessel B=y.

In Vessel C , both acid and water will be in equal quantity. So,

Net quantity of acid = Net quantity of water

20x+14y=15x+21y

5x=7y

x/y=7/5

So, x:y=7 :5

Vessel A : Vessel B = 7:5

(a) is correct option

Right answer is a. 7:5.

is carcat answer 7:5