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80% carbons is present in an alkane by weight. The possible conclusions are

Answer» <html><body><p>The emperical formula of the <a href="https://interviewquestions.tuteehub.com/tag/compound-926863" style="font-weight:bold;" target="_blank" title="Click to know more about COMPOUND">COMPOUND</a> is `CH_(3)`<br/>The minimum number of carbons in the molcule is <a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a> <br/>The compound has gram atoms of C &amp; H in 4:1 ratio <br/>This composition suits to all alkanes</p>Solution :`{:(,"C",,"H"),(,<a href="https://interviewquestions.tuteehub.com/tag/80g-338891" style="font-weight:bold;" target="_blank" title="Click to know more about 80G">80G</a>,,20g),("moles =",(80)/(<a href="https://interviewquestions.tuteehub.com/tag/12-269062" style="font-weight:bold;" target="_blank" title="Click to know more about 12">12</a>),:,(20)/(1)),(,1,:,3):}` <br/> `(n)/(2n+2)=(1)/(3)impliesn=2`</body></html>


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