1.

80% carbons is present in an alkane by weight. The possible conclusions are

Answer»

The emperical formula of the COMPOUND is `CH_(3)`
The minimum number of carbons in the molcule is 2
The compound has gram atoms of C & H in 4:1 ratio
This composition suits to all alkanes

Solution :`{:(,"C",,"H"),(,80G,,20g),("moles =",(80)/(12),:,(20)/(1)),(,1,:,3):}`
`(n)/(2n+2)=(1)/(3)impliesn=2`


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