83.33 gm of 117.6 % oleum is added to 1 litre of 3MK_(4)[Fe(CN)_(6)] and futher 2 litre of 33.6 volume strenght (at 1 atm, 273 K) H_(2)O is added to it reaction: K_(4)[Fe(CN)_(6)]+H_(2)SO_(4) +H_(2)O_(2) rarr K_(3)[Fe(CN)_(6)] +K_(2)SO_(4)+H_(2)O If final volume of solutin is 3 litre , then select the correct statement(s):

83.33 gm of 117.6 % oleum is added to 1 litre of 3MK_(4)[Fe(CN)_(6)] a

1.	83.33 gm of 117.6 % oleum is added to 1 litre of 3MK_(4)[Fe(CN)_(6)] and futher 2 litre of 33.6 volume strenght (at 1 atm, 273 K) H_(2)O is added to it reaction: K_(4)[Fe(CN)_(6)]+H_(2)SO_(4) +H_(2)O_(2) rarr K_(3)[Fe(CN)_(6)] +K_(2)SO_(4)+H_(2)O If final volume of solutin is 3 litre , then select the correct statement(s):
Answer» `H_(2)SO_(4)` is LIMITED reagent 2 moles of `K_(3)Fe(CN)_(6)` is formed If 2 ml of resulting solution is HEATED then 37.3 ml of `O_(2)` at 1 ATM , 273 K will be evoled from `H_(2)O_(2)` If 3 ml of resulting solution is heated then 37.3 ml of `O_(2)` at 1 atm , 273 K will be evolved from `H_(2)O_(2)` Answer :A::B::C