1.

9.00 litres of a gas at 16 atm and 27°C weigh 93.6 g. What is the molecular mass of the gas ?

Answer»

Solution :In the present CASE,
`P=16 atm, V = 9.00 L, T = 27^(@) C = 300 K, w = 93.6 g`
According to the gas EQUATION, `PV = w/M RT`
or `M = (wRT)/(PV)`
SUBSTITUTING the values, we get
`M = (93.6 xx 0.0821 xx 300)/(16 xx 9.00) = 16.01`


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