9.0g m ice at 0^(@)C is mixed with 36gm of water at 50^(@)C in a thermally insulated container, using the following data, answer the question that follow: C_(P (H_(2)O)) = 4.18 Jg^(-1) K^(-1), Delta H_("fusion") (ice) = 335 J g^(-1) Final tempeature of water is

9.0g m ice at 0^(@)C is mixed with 36gm of water at 50^(@)C in a therm

1.	9.0g m ice at 0^(@)C is mixed with 36gm of water at 50^(@)C in a thermally insulated container, using the following data, answer the question that follow: C_(P (H_(2)O)) = 4.18 Jg^(-1) K^(-1), Delta H_("fusion") (ice) = 335 J g^(-1) Final tempeature of water is
Answer» 304.43K 296.97 K 303.93K 287K Solution :If final temperature is T then we can GIVE expression as LIKE this `36 xx 4.18 xx (323- T)` `=9 xx 335 + 9 xx (T - 273) xx 4.18` `48605 - 150.48T = 3015 + 37.62T - 10270.26` On SOLVING, T = 296.97K