9.0g m ice at 0^(@)C is mixed with 36gm of water at 50^(@)C in a thermally insulated container, using the following data, answer the question that follow: C_(P (H_(2)O)) = 4.18 Jg^(-1) K^(-1), Delta H_("fusion") (ice) = 335 J g^(-1) Final tempeature of water is

9.0g m ice at 0^(@)C is mixed with 36gm of water at 50^(@)C in a therm

1.	9.0g m ice at 0^(@)C is mixed with 36gm of water at 50^(@)C in a thermally insulated container, using the following data, answer the question that follow: C_(P (H_(2)O)) = 4.18 Jg^(-1) K^(-1), Delta H_("fusion") (ice) = 335 J g^(-1) Final tempeature of water is
Answer» <html><body><p>304.43K<br/>296.97 K<br/>303.93K<br/>287K</p>Solution :If final temperature is T then we can <a href="https://interviewquestions.tuteehub.com/tag/give-468520" style="font-weight:bold;" target="_blank" title="Click to know more about GIVE">GIVE</a> expression as <a href="https://interviewquestions.tuteehub.com/tag/like-1073845" style="font-weight:bold;" target="_blank" title="Click to know more about LIKE">LIKE</a> this `36 xx 4.18 xx (<a href="https://interviewquestions.tuteehub.com/tag/323-307610" style="font-weight:bold;" target="_blank" title="Click to know more about 323">323</a>- T)` <br/> `=9 xx 335 + 9 xx (T - 273) xx 4.18` <br/> `48605 - 150.48T = 3015 + 37.62T - 10270.26` <br/> On <a href="https://interviewquestions.tuteehub.com/tag/solving-1217196" style="font-weight:bold;" target="_blank" title="Click to know more about SOLVING">SOLVING</a>, T = 296.97K</body></html>