1.

9.8g of an acid of molecuar weight 98 was neutralised by 200ml of one normal caustic soda. What is thebasicity of the acid?

Answer»

Solution :NUMBER of milli EQUIVALENT of BASE `=200xx1=200meq`.
Number of milli equivalent of acid =200m. EQ
200 milli equicalent of acid =?
Equivalent weight of acid `=(9.8xx1000)/(200)=49`
Basicity of acid `=("Molecular weight ")/("Equivalent weight")=(98)/(49)=2`


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