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9.9g of amide with molecular formula C_(4)H_(5)N_(x)O_(y) on heating with alkali liberated 1.7g of ammonia. If the percentage of oxygen is 33.33% then the ratio of 'N' and 'O' atoms in the compound is: |
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Answer» `1:1` `:.` MOLECULAR MASS of amide `=(9.9)/(1.7) xx 17x = 99x` % NITROGEN in the amide `= (14x)/(99x) xx 100 = 14.14` Ratio of number of atoms of 'N' and 'O' `= (14.14)/(14): (33.33)/(16) = 1:2` |
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