A 0.01 M solution of glucose in water freezes at -0.0186^(@)C A 0.01 M solution of KNO_(3) in water will freeze at

A 0.01 M solution of glucose in water freezes at -0.0186^(@)C A 0.01 M

1.	A 0.01 M solution of glucose in water freezes at -0.0186^(@)C A 0.01 M solution of KNO_(3) in water will freeze at
Answer» <html><body><p>`-0.0093^(@)C`<br/>`-0.0372^(@)C`<br/>`-0.0186^(@)C`<br/>`-0.093^(@)C`</p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :`KNO_(3)` ionises as, <br/> `KNO_(3) <a href="https://interviewquestions.tuteehub.com/tag/harr-2692945" style="font-weight:bold;" target="_blank" title="Click to know more about HARR">HARR</a> K^(+) + NO_(3)^(-)` <br/> `therefore` Concentration in solution `=2xx0.01=0.02` <br/> `DeltaT_(f)=T_(f)-T^(@)=K_(f)xxm`for glucose <br/> `therefore k_(f)(<a href="https://interviewquestions.tuteehub.com/tag/deltatf-2053493" style="font-weight:bold;" target="_blank" title="Click to know more about DELTATF">DELTATF</a>)/(m)=(0.018)/(0.01)=1.86^(@) m^(-1)` <br/> `DeltaT_(f)` for `KNO_(3)=1.86xx0.02=0.0372^(@)C` <br/> `T_(f)=T^(@)-T_(f)=0.0000-0.0372=-0.0372^(@)C`</body></html>