A 0.01 M solution of glucose in water freezes at -0.0186^(@)C A 0.01 M solution of KNO_(3) in water will freeze at

A 0.01 M solution of glucose in water freezes at -0.0186^(@)C A 0.01 M

1.	A 0.01 M solution of glucose in water freezes at -0.0186^(@)C A 0.01 M solution of KNO_(3) in water will freeze at
Answer» `-0.0093^(@)C` `-0.0372^(@)C` `-0.0186^(@)C` `-0.093^(@)C` SOLUTION :`KNO_(3)` ionises as, `KNO_(3) HARR K^(+) + NO_(3)^(-)` `therefore` Concentration in solution `=2xx0.01=0.02` `DeltaT_(f)=T_(f)-T^(@)=K_(f)xxm`for glucose `therefore k_(f)(DELTATF)/(m)=(0.018)/(0.01)=1.86^(@) m^(-1)` `DeltaT_(f)` for `KNO_(3)=1.86xx0.02=0.0372^(@)C` `T_(f)=T^(@)-T_(f)=0.0000-0.0372=-0.0372^(@)C`