A 0.05 N solution of acetic acid is found to be 1.9% ionized at 25^(@)C. Calculate (i) K_(a) for acetic acid and(ii) the pH of the solution.

A 0.05 N solution of acetic acid is found to be 1.9% ionized at 25^(@)

1.	A 0.05 N solution of acetic acid is found to be 1.9% ionized at 25^(@)C. Calculate (i) K_(a) for acetic acid and(ii) the pH of the solution.
Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :Amount of <a href="https://interviewquestions.tuteehub.com/tag/acetic-1967065" style="font-weight:bold;" target="_blank" title="Click to know more about ACETIC">ACETIC</a> <a href="https://interviewquestions.tuteehub.com/tag/acid-847491" style="font-weight:bold;" target="_blank" title="Click to know more about ACID">ACID</a> dissociated `=0.5xx1.9//100=0.00095` <br/> `:. ` Concs. At equilibrium : `[CH_(3)<a href="https://interviewquestions.tuteehub.com/tag/co-920124" style="font-weight:bold;" target="_blank" title="Click to know more about CO">CO</a> OH]=0.05-0.00095 M, [CH_(3)CO O^(-)] = [H^(+)] = 0.00095 M`</body></html>