1.

A 0.05 N solution of acetic acid is found to be 1.9% ionized at 25^(@)C. Calculate (i) K_(a) for acetic acid and(ii) the pH of the solution.

Answer»


SOLUTION :Amount of ACETIC ACID dissociated `=0.5xx1.9//100=0.00095`
`:. ` Concs. At equilibrium : `[CH_(3)CO OH]=0.05-0.00095 M, [CH_(3)CO O^(-)] = [H^(+)] = 0.00095 M`


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